4x^2-33x-621=0

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Solution for 4x^2-33x-621=0 equation:



4x^2-33x-621=0
a = 4; b = -33; c = -621;
Δ = b2-4ac
Δ = -332-4·4·(-621)
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11025}=105$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-105}{2*4}=\frac{-72}{8} =-9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+105}{2*4}=\frac{138}{8} =17+1/4 $

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